What is the distance between $(2, 0, –1)$ and $(–1, 4, –2)$ ?

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Answer 1 · 2018-03-31T04:07:16

Distance between $(2,0,-1) and (-1,4,-2)$ is $sqrt 26$ unit.

The distance between two points $P(x_1,y_1,z_1)$ and

$Q(x_2,y_2,z_2)$ in xyz-space is given by formula,

$D=sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2$

Here $P=(2,0,-1) and Q=(-1,4,-2)$

$D(P,Q)=sqrt((-1-2)^2+(4-0)^2+(-2+1)^2$ or

$D(P,Q)=sqrt(9+16+1)= sqrt 26$ unit

Distance between $(2,0,-1) and (-1,4,-2)$ is $sqrt 26$ unit

[Ans]

What is the distance between (2, 0, –1) (2, 0, –1) and (–1, 4, –2) (–1, 4, –2) ?