Question

What is the distance between `(1, 4)` and `(–3, –2)`?

Answer 1

7.21

Explanation:

The formula for distance is simply pythagoras written in different terms.
`d = sqrt((x_2-x_1)^2 + (y_2-y_1)^2`
Substituting and solving we get:
`d = sqrt((1+3)^2 + (4+2)^2`
`d = sqrt(4^2 + 6^2)`
`d = sqrt(16 + 36)`
`d = sqrt(52)`
`d = 7.21`

Answer 2

Distance `= sqrt52 approx 7.2`units

Explanation:

Distance between two points

`= sqrt((x_1-x_2)^2-(y_1-y_2)^2`

Here , `x_1=1`

`x_2=-3`

`y_1=4`

`y_2=-2`

Put these values on the distance formula

`d=> sqrt((1-(-3))^2+(4-(-2)^2`

`d=> sqrt((1+3)^2+(4+2)^2`

`d=> sqrt((4)^2 + (6)^2`

`d=> sqrt(16+36)`

`d=> sqrt52 approx 7.2 " units"`