What is the distance between $(0, 4, –2)$ and $(–1, 4, –2)$ ?

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Answer 1 · 2018-06-14T05:36:06

$d = 1$

The formula for the distance for 3-dimensional coordinates is similar or 2-dimensional; it is: $d = sqrt((x_2-x_1)^2 + (y_2-y_1)^2 + (z_2-z_1)^2)$

We have the two coordinates, so we can plug in the values for $x$ , $y$ , and $z$ :
$d = sqrt((-1-0)^2 + (4-4)^2 + (-2-(-2))^2)$

Now we simplify:
$d = sqrt((-1)^2 + (0)^2 + (-2+2)^2)$

$d = sqrt(1 + 0)$

$d = sqrt(1)$

$d = 1$

Hope this helps!

What is the distance between (0, 4, –2) (0, 4, –2) and (–1, 4, –2) (–1, 4, –2) ?