What is the distance between $(–1, 2, –3)$ and $(–1, 4, –2)$ ?

Question

1487 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-14T17:33:34

$A=(-1,2,-3)" ; "A_x=-1" ; "A_y=2" ; "A_z=-3$

$B=(-1,4,-2)" ; "B_x=-1" ; "B_y=4" ; "B_z=-2$

$Delta x=B_x-A_x=-1+1=0$
$Delta y=B_y-A_y=4-2=2$
$Delta z=B_z-A_z=-2+3=1$

$"The distance between A and B can be calculated using "$

$s_("A,B")=sqrt(Delta x^2+Delta y^2+Delta z^2)$

$s_("A,B")=sqrt(0^2+2^2+1^2)$

$s_("A,B")=sqrt(4+1)$

$s_("A,B")=sqrt(0^2+2^2+1^2)=sqrt 5 " unit"$

What is the distance between (–1, 2, –3) (–1, 2, –3) and (–1, 4, –2) (–1, 4, –2) ?