What is the distance between $(3, 2, 1)$ and $(–1, 4, –2)$ ?

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Answer 1 · 2015-12-07T12:24:21

$sqrt29$

The distance between 2 points $(x1,y1,z1) and (x2,y2,z2)$ = $sqrt((x2-x1)^2+(y2-y1)^2+(z2-z1)^2)$

So, the distance between $(3,2,1) and (-1,4,-2)$ = $sqrt((-1-3)^2+(4-2)^2+(-2-1)^2)$
= $sqrt29$

What is the distance between (3, 2, 1) (3, 2, 1) and (–1, 4, –2) (–1, 4, –2) ?