What is the distance between $(3, 4, 1)$ and $(3, 6, 2)$ ?

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Answer 1 · 2015-12-06T13:35:13

$sqrt5$

Distance between 2 points $(x1,y1,z1) and (x2,y2,z2)$ = $sqrt((x2-x1)^2+(y2-y1)^2+(z2-z1)^2)$

So distance between (3,4,1) and (3,6,2) = $sqrt((3-3)^2+(6-4)^2+(2-1)^2)$

= $sqrt5$

What is the distance between (3, 4, 1) (3, 4, 1) and (3, 6, 2) (3, 6, 2) ?