What is the distance between $(1,3,-3)$ and $(-2,1,-3)$ ?

Question

3917 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-23T14:35:11

The distance between $(1,3,-3)$ and $(-2,1,-3)$ is $3.6056$ .

The distance between two points $(x _1,y_1,z_1)$ and $(x _2,y_2,z_2)$ is given by

$sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)$ .

Hence distance between $(1,3,-3)$ and $(-2,1,-3)$ is

$sqrt((-2-1)^2+(1-3)^2+(-3-(-3))^2)$

= $sqrt((-3)^2+(-2)^2+0^2)$

= $sqrt(9+4+0)$

= $sqrt13=3.6056$

What is the distance between (1,3,-3)(1,3,-3) and (-2,1,-3)(-2,1,-3)?