The length of the perpendicular drawn from the point (a,3) on the line 3x+4y+5=03x+4y+5=0 is 4, how do you find the value of a?

1 Answer
Oct 18, 2016

a=1 or a=-37/3a=1ora=373

Explanation:

We know perpendicular distance (D) from a point (m,n)(m,n) to a line of equation Ax+By+C=0 ; D= |Am+Bn+C|/sqrt(A^2+B^2)Ax+By+C=0;D=|Am+Bn+C|A2+B2
So here ,4= |3a+4*3+5|/sqrt(3^2+4^2) or |3a+17|=20 :. 3a+17=20 or a=1 Also 3a+17=-20 or a=-37/3 :.
a=1 or a=-37/3[Ans]