What is the distance between (2, -3) and (5, -4)?

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Answer 1 · 2016-10-01T00:31:30

$\sqrt{58}$ $sqrt(58)$ units

We have: $(2, - 3)$ $(2, - 3)$ and $(5, - 4)$ $(5, - 4)$

Let's apply the distance formula:

$\Rightarrow d = \sqrt{{(x_{2} - x_{1})}_{2}^{2} + {(y_{2} - y_{1})}_{2}^{2}}$ $=> d = sqrt((x_(2) - x_(1))^(2) + (y_(2) - y_(1))^(2))$

$\Rightarrow d = \sqrt{{(5 - 2)}^{2} + {(- 4 - (- 3))}^{2}}$ $=> d = sqrt((5 - 2)^(2) + (- 4 - (- 3))^(2))$

$\Rightarrow d = \sqrt{3^{2} + {(- 7)}^{2}}$ $=> d = sqrt(3^(2) + (- 7)^(2))$

$\Rightarrow d = \sqrt{9 + 49}$ $=> d = sqrt(9 + 49)$

$\Rightarrow d = \sqrt{58}$ $=> d = sqrt(58)$

Therefore, the distance between the two points $(2, - 3)$ $(2, - 3)$ and $(5, - 4)$ $(5, - 4)$ is $\sqrt{58}$ $sqrt(58)$ units.