What is the distance between $(–2, 2, 6)$ and $(–1, 1, 3)$ ?

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Answer 1 · 2016-07-31T15:42:10

Distance between $(-2,2,6)$ and $(-1,1,3)$ is $sqrt11=3.317$

The distance between two points $(x_1,y_1,z_1)$ and $(x_2,y_2,z_2)$ is given by

$sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)$

Hence distance between $(-2,2,6)$ and $(-1,1,3)$ is

$sqrt(((-1)-(-2))^2+(1-2)^2+(3-6)^2)$

= $sqrt((-1+2)^2+(-1)^2+(-3)^2)$

= $sqrt(1^2+1+9)$

= $sqrt11$

= $3.317$

Answer 2 · 2016-07-31T15:50:52

The distance between to points $(x_1, x_2, x_3)$ and $(y_1, y_2, y_3)$ in the 3-dimensional space is $sqrt((x_1-y_1)^2+ (x_2-y_2)^2+ (x_3-y_3)^2$

Now simply replacing $(x_1, x_2, x_3)$ and $(y_1, y_2, y_3)$ by the values given we have:

$sqrt((-2+1)^2+ (2-1)^2+ (6-3)^2)=sqrt((-1)^2+ (1)^2+ (3)^2)=sqrt(11)$

which is the distance

What is the distance between (–2, 2, 6) (–2, 2, 6) and (–1, 1, 3) (–1, 1, 3) ?