What is the distance between (3, –1, 1) and (6, 0, 4) ?

1 Answer
Mar 5, 2018

See a solution process below:

Explanation:

The formula for calculating the distance between two points is:

d = sqrt((color(red)(x_2) - color(blue)(x_1))^2 + (color(red)(y_2) - color(blue)(y_1))^2 + (color(red)(z_2) - color(blue)(z_1))^2)

Substituting the values from the points in the problem gives:

d = sqrt((color(red)(6) - color(blue)(3))^2 + (color(red)(0) - color(blue)(-1))^2 + (color(red)(4) - color(blue)(1))^2)

d = sqrt((color(red)(6) - color(blue)(3))^2 + (color(red)(0) + color(blue)(1))^2 + (color(red)(4) - color(blue)(1))^2)

d = sqrt(3^2 + 1^2 + 3^2)

d = sqrt(9 + 1 + 9)

d = sqrt(19)

Or

d = 4.359 rounded to the nearest thousandth.