What is the distance between (0, 0, 8) and (3, 4, 1) ?

1 Answer
Dec 23, 2015

sqrt{74} approx 8.6

Explanation:

By the distance formula, the distance between two points P and Q whose rectangular coordinates are (x_{1},y_{1},_z_{1}) and (x_{2},y_{2},z_{2}) is

sqrt{(x_{1}-x_{2})^2+(y_{1}-y_{2})^2+(z_{1}-z_{2})^2}

For the problem at hand, this is

sqrt{(3-0)^2+(4-0)^2+(1-8)^2}=sqrt{9+16+49}=sqrt{74} approx 8.6.