How do you find the value of a given the points (-9,7), (a,5) with a distance of $\sqrt{29}$ $sqrt29$ ?

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Answer 1 · 2016-07-08T16:29:10

$a = - 4$ $a=-4$ or $a = - 15$ $a = -15$

$29 = {(- 9 - a)}^{2} + {(7 - 5)}^{2}$ $29=(-9-a)^2 +(7-5)^2$

Simplify , $29 = {(9 + a)}^{2} + 4$ $29=(9+a)^2 +4$

Or, $25 = {(9 + a)}^{2}$ $25=(9+a)^2$

Or, $9 + a = \pm 5$ $9+a=pm5$

so

$a = - 4$ $a=-4$ or $a = - 15$ $a = -15$

How do you find the value of a given the points (-9,7), (a,5) with a distance of sqrt29√29sqrt29?