How do you find the value of a given the points (-9,7), (a,5) with a distance of #sqrt29#?

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Answer 1 · 2016-07-08T16:29:10

#a=-4# or #a = -15#

#29=(-9-a)^2 +(7-5)^2#

Simplify , #29=(9+a)^2 +4#

Or, #25=(9+a)^2#

Or, #9+a=pm5#

so

#a=-4# or #a = -15#