What is the distance between #(1, -3) # and #(-4, 3) #?

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Answer 1 · 2015-12-19T22:21:44

#sqrt(61)#

Find the distance between the two #x# points

#abs(-4-1) = 5#

Next find the distance between the two #y# points

#abs(3-(-3)) = 6#

Use the pythagorean theorem

#a^2+b^2=c^2#

where #a=5# and #b=6#

Solve for c

#c=sqrt(25+36)#

Finally

#c=sqrt(61)#