What is the distance between P(4,1) and Q(12,-5)?

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What is the distance between P(4,1) and Q(12,-5)?

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Answer 1 · 2016-03-18T16:16:39

$distance= 10 u n i t$ $"distance="10" "unit$

Explanation:

$P (x, y) Q (a, b)$ $P(x,y) " "Q(a,b)$
$distance= \sqrt{{(a - x)}^{2} + {(b - y)}^{2}}$ $"distance="sqrt((a-x)^2+(b-y)^2$
$distance: = \sqrt{{(12 - 4)}^{2} + {(- 5 - 1)}^{2}}$ $"distance:"=sqrt((12-4)^2+(-5-1)^2$
$distance= \sqrt{8^{2} + {(- 6)}^{2}}$ $"distance="sqrt(8^2+(-6)^2)$
$distance= \sqrt{64 + 36}$ $"distance="sqrt(64+36)$
$distance= \sqrt{100}$ $"distance="sqrt100$
$distance= 10 u n i t$ $"distance="10" "unit$

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What is the distance between P(4,1) and Q(12,-5)?

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