What is the distance between $(3,5)$ and $(6,2)$ ?

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Answer 1 · 2018-05-13T03:10:10

I tried this:

Here you can use for the distance $d$ the following expression (derived from Pythagoras Theorem):

$d=sqrt((x_2-x_1)^2+(y_2-y_1)^2)$

using the coordinates of your points:

$d=sqrt((6-3)^2+(2-5)^2)=sqrt(9+9)=sqrt(18)=4.2$ units

Answer 2 · 2018-05-13T03:19:20

$d = 4.24$

First, we start with the distance formula

$d = sqrt((X_2 - X_1)^2 + (Y_2 - Y_1)^2$

Coordinates are always in $(X,Y)$

So in $(3,5)$ , we'll make our $3$ the $X_2$
So the $5$ is the $Y_2$

This means that in $(6,2)$ , the $6$ is the $X_1$
And the $2$ is the $Y_1$

Now we plug our $X$ and $Y$ into the equation

$d = sqrt((3 - 6)^2 + (5 - 2)^2$

$d = sqrt(( -3)^2 + ( 3)^2$

$d = sqrt(9 + 9)$

$d = sqrt18$ $~~$ $4.24$

What is the distance between (3,5)(3,5) and (6,2)(6,2)?