What is the distance between (-15,36) and (–3, 2) ?

1 Answer
Jul 25, 2018

The distance is 10sqrt13 or about 36.056 (rounded to nearest thousandth's place).

Explanation:

The formula for the distance of 2-dimensional coordinates is: d = sqrt((x_2-x_1)^2 + (y_2-y_1)^2)

We have the two coordinates, so we can plug in the values for x and y:
d = sqrt((-3-(-15))^2 + (2-36)^2)

Now we simplify:
d = sqrt((12)^2 + (-34)^2)

d = sqrt(144 + 1156)

d = sqrt(1300)

d = 10sqrt13

If you want to leave it in exact form, you can leave the distance as 10sqrt13. However, if you want the decimal answer, here it is rounded to the nearest thousandth's place:
d ~~ 36.056

Hope this helps!