What is the distance between $(–6, 3, 1)$ and $(0, 4, –2)$ ?

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Answer 1 · 2016-07-02T07:42:22

The distance between $(-6,3,1)$ and $(0,4,-2)$ is $6.782$

In a two dimensional plane, distance between two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by

$sqrt((x_2-x_1)^2+(y_2-y_1)^2)$

and in three dimensional space, distance between two points $(x_1,y_1,z_1)$ and $(x_2,y_2,z_2)$ is given by

$sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)$

Hence, the distance between $(-6,3,1)$ and $(0,4,-2)$ is

$sqrt((0-(-6))^2+(4-3)^2+(-2-1)^2)$

= $sqrt(6^2+1^2+(-3)^2)=sqrt(36+1+9)=sqrt46=6.782$

What is the distance between (–6, 3, 1) (–6, 3, 1) and (0, 4, –2) (0, 4, –2) ?