What is the distance between $(-5,13,-14)$ and $(-11,4,1)$ ?

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Answer 1 · 2016-04-15T15:50:18

$=> L=3sqrt(38)" " ~~" "18.493$ to 3 decimal places

Treat the way you would a triangle using Pythagoras but with 3 values instead of two.

Let the length between the two points be L

Let point 1 $->P_1->(x_1,y_1,z_1)->(-5,13,-14)$
Let point 2 $->P_2->(x_2,y_2,z_2)->(-11,4,1)$

Then

$L^2=(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2$

So $L=sqrt( ( -11-[-5])^2+( 4-13)^2+(1-[-14])^2)$

$L=sqrt(36+81+225) =sqrt(342)$

But $342= 2xx3^2xx19$ but both 19 and 2 are prime numbers

$=> L=3sqrt(38)$

What is the distance between (-5,13,-14)(-5,13,-14) and (-11,4,1)(-11,4,1)?