What is the distance between $(–6, 3, 1)$ and $(4, 4, 2)$ ?

Question

1378 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-16T07:16:41

The distance between $(-6,3,1)$ and $(4,4,2)$ is $12.083$

Just like $(x,y)$ represents a point on a plane i.e. in $2$ -dimension,

$(x,y,z)$ represents a point in $3$ -dimension.

and distance between two points $(x_1,y_1,z_1)$ and $(x_2,y_2,z_2)$ is

$sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)$

Therefore, distance between $(-6,3,1)$ and $(4,4,2)$ is

$sqrt((6-(-6))^2+(4-3)^2+(2-1)^2)$

= $sqrt((6+6)^2+(4-3)^2+(2-1)^2)$

= $sqrt(12^2+1^2+1^2)=sqrt(144+1+1)=sqrt146=12.083$

What is the distance between (–6, 3, 1) (–6, 3, 1) and (4, 4, 2) (4, 4, 2) ?