What is the distance between (11,−13,−5) and (9,−14,4)?

1 Answer
Jim G.
Mar 21, 2018

√86≈9.27 to 2 dec. places

Explanation:

using the 3-d version of the distance formula

∙xd=√(x2−x1)2+(y2−y1)2+(z2−z1)2

let (x1,y1,z1)=(11,−13,−5) and

(x2,y2,z2)=(9,−14,4)

d=√(9−11)2+(−14+13)2+(4+5)2

d=√4+1+81=√86≈9.27

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