What is the distance between $(–2, 1, 3)$ and $(2, 0, –1)$ ?

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Answer 1 · 2016-07-11T21:32:24

$s=sqrt(33)" unit"$

$A=(-2,1,3)$
$A_x=-2" ; "A_y=1" ; "A_z=3$

$B=(2,0,-1)$
$B_x=2" ; "B_y=0" ; "B_z=-1$

$"the distance between A and B can be calculated using:"$

$s=sqrt((B_x-A_x)^2+(B_y-A_y)^2+(B_z-A_z)^2)$

$s=sqrt((2+2)^2+(0-1)^2+(-1-3)^2)$

$s=sqrt(4^2+(-1)^2)+(-4)^2$

$s=sqrt(16+1+16)$

$s=sqrt(33)" unit"$

What is the distance between (–2, 1, 3) (–2, 1, 3) and (2, 0, –1) (2, 0, –1) ?