What is the distance between $(–2, 0, 1)$ and $(0, 4, –2)$ ?

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Answer 1 · 2018-03-05T18:57:56

$d=2sqrt14$

The distance between two points $(x_1,y_1,z_1)$ and $(x_2,y_2,z_2)$ in 3-space is given by the following formula

$d=sqrt ((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)$

In the case of $(-2,0,4)$ and $(0,4,-2)$ , the distance between them is

$d=sqrt((0--2)^2+(4-0)^2+(-2-4)^2)=sqrt(4+16+36)=sqrt56=2sqrt14$

What is the distance between (–2, 0, 1) (–2, 0, 1) and (0, 4, –2) (0, 4, –2) ?