How do you factor #36x ^ { 4} - 27x ^ { 3} + 45x ^ { 2}#?

1 Answer
Jun 7, 2017

#9x^2(4x^2-3x+5)#

Explanation:

To factor out the problem we need to figure out the factor of #35,-27, and 45#.

#9# is our magic number, we also need to factor out #x# to do this we get the smallest amount of #x# that is available which is #x^2#.

So, our factor is #9x^2#.

#9x^2(4x^2-3x+5)# is the answer. To check this you can distribute it out and you will arrive to the original problem.