How do you write the equation of a line that passes through (-4, 3) and (2, 6)?

1 Answer
Jun 7, 2017

See below.

Explanation:

We first need to find the slope of the line.

slope=632(4)=36=12

We know that the equation of a line takes on the form y=mx+b, where m is the slope and b is the y-intercept.

Thus, we can plug in our answer to get:

y=12x+b

However, we know a point (x,y) on this line-- (2,6). We can plug this in as well.

6=12(2)+b

6=1+b

b=5.

So, our final equation is:

y=12x+5