How do you find the period, amplitude and sketch #y=sin(x-pi)#?

1 Answer
Jun 12, 2017

Period= 2#pi# ;
Amplitude=1;
graph{sin(x-pi) [-10, 10, -5, 5]}

Explanation:

It is Simple!

Period:
Period is the complete revolution of a wave completing crest and followed by trough. So, for this sine function , the period is 2 #pi#.
Because, it becomes zero at first # #x#= pi#, and then completing one crest, becomes zero at # #x#= 2pi#. And, then completing one trough becomes zero # #x#= 3pi#. So, it had completed one revolutions , difference in #x# on both sides is #2pi#. Hence, the period is #2pi#.

Amplitude:
Next, we want to that this function attains a maximum value of 1 at both sides of #x#-axis. So, for every wave like function (here, sine function), the general equation is #y=asin(z)#, where #a# is the amplitude. Here the amplitude is 1!.

Graph-Refer.:
https://www.google.co.in/search?q=period+of+sin+x&oq=period+of+sin+x&aqs=chrome..69i57j69i60j0l4.4393j0j7&sourceid=chrome&ie=UTF-8#q=y+%3D+sin+(+x+%E2%88%92+%CF%80+)