How do you multiply $3 y^{0} \cdot 2 x y^{2}$ $3y ^ { 0} \cdot 2x y ^ { 2}$ ?

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Answer 1 · 2017-06-13T02:13:09

$3 y^{0} \cdot 2 x y^{2} = 6 x y^{2}$ $3y^0*2xy^2=6xy^2$

Since any number raised to the power $0$ $0$ equals $1$ $1$

$3 y^{0} \cdot 2 x y^{2} = 3 (1) \cdot 2 x y^{2}$ $3y^0*2xy^2=3(1)*2xy^2$

And since any number times $1$ $1$ is itself

$3 y^{0} \cdot 2 x y^{2} = 3 \cdot 2 x y^{2}$ $3y^0*2xy^2=3*2xy^2$

Then we multiply $2 x y^{2}$ $2xy^2$ by $3$ $3$

$3 y^{0} \cdot 2 x y^{2} = 6 x y^{2}$ $3y^0*2xy^2=6xy^2$

How do you multiply 3y0⋅2xy23y ^ { 0} \cdot 2x y ^ { 2}?