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Question #68ee9

1 Answer

Jun 14, 2017

${sec}^{2} (x)$ $sec^2(x)$

Explanation:

$csc (x) = \frac{1}{sin (x)}$ $csc(x)=1/sin(x)$

$tan (x) = \frac{sin (x)}{cos (x)}$ $tan(x)=sin(x)/cos(x)$

$sec (x) = \frac{1}{cos (x)}$ $sec(x)=1/cos(x)$

Multiplying these terms together gives

$1/cancel(sin(x)) cancel(sin(x))/cos(x) 1/cos(x)=1/cos^2(x)=sec^2(x)$

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