How do you simplify $(- 3 i - 6) - (3 - 7 i) + (- 11 - 8 i)$ $(- 3i - 6) - ( 3- 7i ) + ( - 11- 8i )$ ?

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Answer 1 · 2017-06-18T02:45:43

$- 20 - 4 i$ $-20-4i$

First we distribute the expression:

$(- 3 i - 6) - (3 - 7 i) + (- 11 - 8 i)$ $(-3i-6)-(3-7i)+(-11-8i)$

$- 3 i - 6 - 3 + 7 i - 11 - 8 i$ $-3i-6-3+7i-11-8i$

Now combine like terms:

$- 3 i + 7 i - 8 i - 6 - 3 - 11$ $-3i+7i-8i-6-3-11$

Simplify:

$- 4 i - 20$ $-4i-20$

The Standard form is $a + b i$ $a+bi$
Where $a$ $a$ is the real part.
Where $b$ $b$ is the imaginary part.

$- 20 - 4 i$ $-20-4i$ or $- (20 + 4 i)$ $-(20+4i)$

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How do you simplify (- 3i - 6) - ( 3- 7i ) + ( - 11- 8i )(−3i−6)−(3−7i)+(−11−8i)(- 3i - 6) - ( 3- 7i ) + ( - 11- 8i )?