How do you solve #8( w + 6) = 2w + 12#?

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Answer 1 · 2017-06-21T00:11:05

#w=-6#

First you distribute the left:

#8(w+6)=8w+48#

This is what we got so far:

#8w+48=2w+12#

What you do now is subtract #2w# from both sides:

#8w-2w+48=cancel2w-cancel2w+12#

#6w+48=12#

Now subtract #48# from both sides:

#6w+cancel48-cancel48=12-48#

#6w=-36#

Now divide both sides by #6#

#(cancel6w)/cancel6=-36/6#

#w=-6#