How do you identify the vertex for ${(x + 3)}^{2} = - 8 (y - 2)$ $( x + 3) ^ { 2} = - 8( y - 2)$ ?

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Answer 1 · 2017-06-21T13:08:02

Vertex = $(- 3, 2)$ $(-3, 2)$

The vertex is identified from this formula.

$a {(x - x_{1})}_{1}^{2}$ $a(x - x_1)^2$ = $(y - y_{1})$ $(y - y_1)$

Whatever what x_1 equals to is the $x$ $x$ -coordinate of the vertex. Whatever what $y_{1}$ $y_1$ is the $y$ $y$ -coordinate of the vertex.

In our case,

$x_{1}$ $x_1$ = -3 and $y_{1}$ $y_1$ = 2

How do you identify the vertex for (x+3)2=−8(y−2)( x + 3) ^ { 2} = - 8( y - 2)?