How do you add \frac { 4x } { 3x - 1} + \frac { 9} { x + 4}4x3x1+9x+4?

1 Answer
Jun 22, 2017

(4x^2+43x-9)/((3x-1)(x+4))4x2+43x9(3x1)(x+4)

Explanation:

The denominators must be the same in order to add fractions.

(4x)/(3x-1)(x+4)/(x+4)+(3x-1)/(3x-1)9/(x+4)4x3x1x+4x+4+3x13x19x+4

(4x^2+16x)/((3x-1)(x+4))+(27x-9)/((3x-1)(x+4))4x2+16x(3x1)(x+4)+27x9(3x1)(x+4)

(4x^2+16x+27x-9)/((3x-1)(x+4))4x2+16x+27x9(3x1)(x+4)

(4x^2+43x-9)/((3x-1)(x+4))4x2+43x9(3x1)(x+4)

Because the numerator does not factor (at least not to anything nicely), this completes the addition.