How do you add \frac { 4x } { 3x - 1} + \frac { 9} { x + 4}?

1 Answer
Jun 22, 2017

(4x^2+43x-9)/((3x-1)(x+4))

Explanation:

The denominators must be the same in order to add fractions.

(4x)/(3x-1)(x+4)/(x+4)+(3x-1)/(3x-1)9/(x+4)

(4x^2+16x)/((3x-1)(x+4))+(27x-9)/((3x-1)(x+4))

(4x^2+16x+27x-9)/((3x-1)(x+4))

(4x^2+43x-9)/((3x-1)(x+4))

Because the numerator does not factor (at least not to anything nicely), this completes the addition.