Question #edd42

1 Answer
Jul 1, 2017

=e^x+3/(xln(10))

Explanation:

The final answer depends on whether log(x) is to be interpreted as the log_10(x) or log_e(x)=ln(x) (the natural logarithm). Let's assume you meant the log base 10.

d/dx(e^x+3log_10(x))

=d/dx(e^x)+d/dx(3log_10(x))

=e^x+3d/dx(log_10(x))

Using the change of base formula

=e^x+3d/dx(ln(x)/ln(10))

=e^x+3/ln(10)d/dx(ln(x))

=e^x+3/ln(10)(1/x)

=e^x+3/(xln(10))