How do you solve $\frac { 5} { 6} - \frac { m } { 3} = \frac { 1} { 9}$ ?

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Answer 1 · 2017-07-04T20:58:53

$m=13/6$

Get common denominator $(18)$ to give:
$15/18 - (6m)/18 = 2/18$

You can then clear the $18$ to give:

$15-6m = 2$

Rearrange and solve to give the answer above

Answer 2 · 2017-07-04T20:59:49

$m = 13/6$

If you have an equation which has fractions, you can get rid of the denominators by multiplying by the LCM of the denominators.

$5/6 -m/3 = 1/9" "larr$ In this case the LCD is $18$

$(18xx5)/6 -(18xxm)/3 = (18xx1)/9" "larr$ multiply each term by $18$

$(cancel18^3xx5)/cancel6 -(cancel18^6xxm)/cancel3 = (cancel18^2xx1)/cancel9 "larr$ cancel the denominators

$15-6m = 2$

$15-2 = 6m$

$13= 6m$

$m = 13/6$

How do you solve \frac { 5} { 6} - \frac { m } { 3} = \frac { 1} { 9}\frac { 5} { 6} - \frac { m } { 3} = \frac { 1} { 9}?