How do you evaluate $\frac { x ^ { 2} - 11x + 28} { x - 4} \cdot \frac { 2x } { x - 7}$ ?

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Answer 1 · 2017-07-04T22:10:01

$2x$

Factorise the first numerator to give $(x-4)(x-7)$

$((x-4)(x-7))/(x-4) xx (2x)/(x-7)$

The $(x-4)$ will cancel with the one below and the $(x-7)$ will cancel with the one to the bottom right

$(cancel((x-4))cancel((x-7)))/cancel((x-4)) xx (2x)/cancel((x-7))$

leaving $2x$

How do you evaluate \frac { x ^ { 2} - 11x + 28} { x - 4} \cdot \frac { 2x } { x - 7}\frac { x ^ { 2} - 11x + 28} { x - 4} \cdot \frac { 2x } { x - 7}?