How do you solve $- (x + 3) + 2 x - 1 = 6$ $- ( x + 3) + 2x - 1= 6$ ?

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Answer 1 · 2017-07-05T05:10:24

$x = 10$ $x=10$

First distribute the negative sign in $- (x + 3) + 2 x - 1 = 6$ $−(x+3)+2x−1=6$

$- x - 3 + 2 x - 1 = 6$ $−x-3+2x−1=6$

Combine the like terms. $x - 4 = 6$ $x-4=6$

Add 4 to each side $x = 10$ $x=10$

How do you solve −(x+3)+2x−1=6- ( x + 3) + 2x - 1= 6?