How do you solve $- ( x + 3) + 2x - 1= 6$ ?

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Answer 1 · 2017-07-05T05:10:24

$x=10$

First distribute the negative sign in $−(x+3)+2x−1=6$

$−x-3+2x−1=6$

Combine the like terms. $x-4=6$

Add 4 to each side $x=10$

How do you solve - ( x + 3) + 2x - 1= 6- ( x + 3) + 2x - 1= 6?