How do you solve #-11t + 8( 2t - 6) = 2#?

1 Answer
Jul 6, 2017

#t = 10#

Explanation:

In order to solve this, you need to expand #8(2t-6)# first. Expanding this, you will get #16t - 48#.

Replacing #8(2t-6)# with what we just got, we will get: #-11t + 16t - 48 = 2#.

We can combine #-11t# with #16t#, i.e. #-11t + 16t = 5t#, which will result in a #5t#.

Writing out the equation again with our new computation included, we will get: #5t - 48 = 2#.

Then we need to get rid of the constant #-48# so we add #48# to both sides and we will end up with #5t = 50#. Divide both sides by five and #t = 10#.

If we plug in #10# for t, we should get 2.