How do you solve #\frac{- x - 3}{x + 2} \leq 0#?
2 Answers
HI
given equation,
thus ,to solve this question we need to get the denominator term
thus
=
=
now,
getting minus sign common,
from first term,
=
=-1
as this term is less than and equal to zero
hence,
-1<=
now,getting (x+2) to the numerator side to left and minus one to right
And x cannot be equal to -2 as at x=-2 the given equation is not defied as denominator is 0
thus ,x can be greater than -2 upto positive infinity
Solution :
Explanation:
Crirical points are
Crirical points are
Sign change:
Interval ----------- Sign of
When
When
When
When
Solution :
graph{(-x-3)/(x+2) [-11.25, 11.25, -5.625, 5.62]} [Ans]