A rectangular garden has a length of $(y + 2)$ $(y+2)$ yards and a width of $(4 y - 1)$ $(4y-1)$ yards. How do you find the perimeter of the garden in terms of $y$ $y$ ?

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Answer 1 · 2017-07-15T12:51:28

$P = 10 y + 2$ $P=10y+2$

We will sum the length of the sides:

$(y + 2) + (y + 2) + (4 y - 1) + (4 y - 1)$ $(y+2)+(y+2)+(4y-1)+(4y-1)$

and get the perimeter of the garden in terms of y by finding and summing the like terms:

$P = y + 2 + y + 2 + 4 y - 1 + 4 y - 1$ $P=color(red)y+2color(red)(+y)+2color(red)(+4y)-1color(red)(+4y)-1$

that's

$P = 10 y + 2$ $P=10y+2$

A rectangular garden has a length of (y+2)(y+2) yards and a width of (4y−1)(4y-1) yards. How do you find the perimeter of the garden in terms of yy?