How do you integrate $\int _ { 0} ^ { 3} 5x + 3$ ?

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Answer 1 · 2017-07-15T21:28:23

$63/2$

$int_0^3(5x+3)dx=[5/2x^2+3x]""_0^3$

$(5/2(3^2)+3(3))-(0+0)$

$45/2+18/2$ common denominators

$63/2$

How do you integrate \int _ { 0} ^ { 3} 5x + 3\int _ { 0} ^ { 3} 5x + 3?