How do you solve $\frac{3}{4} v - \frac{1}{2} = - \frac{8}{3}$ $\frac { 3} { 4} v - \frac { 1} { 2} = - \frac { 8} { 3}$ ?

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Answer 1 · 2017-07-21T02:55:02

First, use simple addition for combining the constants and then use the multiplication and the LCM the Least Common Multiple to solve for v.

$\frac{3}{4} v - \frac{1}{2} = - \frac{8}{3}$ $3/4v - 1/2 = -8/3$

Use multiplication and addition to combine -1/2 and -8/3.

$\frac{3}{4} v = - \frac{13}{6}$ $3/4v = -13/6$

Now, use multiplication to solve for v.

$v = - \frac{13}{6} \cdot \frac{4}{3}$ $v= -13/6*4/3$

$v = - \frac{13}{9}$ $v=-13/9$

How do you solve 34v−12=−83\frac { 3} { 4} v - \frac { 1} { 2} = - \frac { 8} { 3}?