How do you simplify ${(\frac{4 x^{9} y^{5}}{z^{3}})}^{2}$ $(\frac { 4x ^ { 9} y ^ { 5} } { z ^ { 3} } ) ^ { 2}$ ?

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Answer 1 · 2017-07-22T02:12:04

Just use simple basic concepts of Algebra to distribute the exponents to the corresponding terms in the parentheses.

${(\frac{4 x^{9} y^{5}}{z^{3}})}^{2}$ $((4x^9y^5)/(z^3))^2$

Distribute the square exponent to all of the terms within the exponent.

$= \frac{16 x^{18} y^{10}}{z^{9}}$ $= (16x^18y^10)/(z^9)$

And since all of the variables are different, this is the answer.

How do you simplify (\frac { 4x ^ { 9} y ^ { 5} } { z ^ { 3} } ) ^ { 2}(4x9y5z3)2(\frac { 4x ^ { 9} y ^ { 5} } { z ^ { 3} } ) ^ { 2}?