How do you solve #x( x + 2) = - 9#?

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Answer 1 · 2017-07-22T04:24:58

All you need to do is to get the quadratic formula:
#-b+-sqrt(b^2-4ac)/(2a)#
and plug the values in as is.

#x(x+2)=-9#

Use the order of operations to simplify and combine the equation into one polynomial #ax^2+bx+c#.

#x^2+2x+9=0#

Plug the values in the quadratic formula as shown in the polynomial.

#-2+-sqrt(2^2-4(1)(9))/(2(1))#

Simplify the equation into its solutions.

#=(-2+-sqrt4-36)/2#
#=(-2+-4isqrt2)/2#
#=-1+-2isqrt2#