How do you solve $- \frac{2}{3} = \frac{5}{3} v - \frac{5}{9}$ $-\frac { 2} { 3} = \frac { 5} { 3} v - \frac { 5} { 9}$ ?

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Answer 1 · 2017-07-22T05:13:50

For this answer, just make sure to figure out the LCD; or Least Common Denominator and solve for $x$ $x$ afterwards.

$- \frac{2}{3} = \frac{5}{3} v - \frac{5}{9}$ $-2/3=5/3v-5/9$

Since the Least Common Denominator is $9$ $9$ , we can multiply the number into all of the terms to make them into easy-to-handle whole numbers.

$- 6 = 15 v - 5$ $-6=15v-5$
$15 v = - 1$ $15v=-1$
$v = - \frac{1}{15}$ $v=-1/15$

Answer 2 · 2017-07-22T05:16:24

$- \frac{2}{3} = \frac{5}{3} v - \frac{5}{9}$ $-2/3 = 5/3v - 5/9$ Equation

$- \frac{1}{9} = \frac{5}{3} v$ $-1/9 = 5/3v$ **Add $\frac{5}{9}$ $5/9$ to $- \frac{2}{3}$ $-2/3$ **

$v = - \frac{1}{15}$ $v = -1/15$ **Divide both sides by $\frac{5}{3}$ $5/3$ **

I hope that helps.

How do you solve −23=53v−59-\frac { 2} { 3} = \frac { 5} { 3} v - \frac { 5} { 9}?