How do you solve $\frac{x + 3}{2} + \frac{2 x}{7} = 7$ $\frac { x + 3} { 2} + \frac { 2x } { 7} = 7$ ?

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Answer 1 · 2017-07-22T05:42:20

A good way to solve this problem is by multiplying the terms with the LCD; or the Least Common Denominator.

$\frac{x + 3}{2} + \frac{2 x}{7} = 7$ $(x+3)/2+(2x)/7=7$

Multiply the terms with 14; the Least Common Denominator of the three terms within the equation.

$7 (x + 3) + 2 (2 x) = 98$ $7(x+3) +2(2x)=98$

Now, just solve for x.

$7 x + 21 + 4 x = 98$ $7x+21+4x=98$

$11 x = 77$ $11x=77$

$x = 7$ $x=7$

How do you solve x+32+2x7=7 \frac { x + 3} { 2} + \frac { 2x } { 7} = 7?