How do you solve 32(x10)2=12?

1 Answer
Jul 22, 2017

x={30+33,3033}

Explanation:

32(x10)2=12
Multiply both by 2
3(x10)2=1
3(x220+100)=1
3x260+300=1
3x260+299=0

We know that if ax2+bx+c=0 then x=b±b24ac2a

So x=(60)±6024329923
x=60±360035886
x=60±126
x=60±236
x=30±33

So, x=30+33 or x=3033