How do you solve the system of equations 5x−2y=2.25 and 7x−4y=3?

1 Answer
Martha W.
Jul 25, 2017

See below

x=0.5 y=0.125

Explanation:

To solve 5x−2y=2.25 and 7x−4y=3, multiply the first equation by −2 and add them.

−2⋅(5x−2y=2.25)=−10x+4y=−4.5

−10x+4y=−4.5
7x−4y=3 then add

you will get −3x=−1.5
divide both sides by −3
x=0.5

substitute this into one of the original equations
5(0.5)−2y=2.25
2.5−2y=2.25
subtract 2.5 from both sides to get −2y=−0.25
divide both sides by −2
y=0.125

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