How do you divide $(42x ^ { 4} - 35x ^ { 3} + 35x ) \div 7x$ ?

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Answer 1 · 2017-07-26T17:08:08

$6x^3-5x^2+5$

As it's a single term on the denominator $(7x)$ , you can divide each term in the numerator separately:

$frac(42x^4)(7x)=6x^3$

$frac(-35x^3)(7x)=-5x^2$

$frac(35x)(7x)=5$

How do you divide (42x ^ { 4} - 35x ^ { 3} + 35x ) \div 7x(42x ^ { 4} - 35x ^ { 3} + 35x ) \div 7x?