Question #a8413

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Answer 1 · 2017-07-27T01:44:57

$5(7)^(2x )= 80$

$7^(2x) = 16$

$x = 1/2log_7(16)$

Now, plug in x.

$7^(3/4x)= 7^(3/8log_7(16))$

$= 7^(log_7(16^(3/8)))$

$=16^(3/8) = 2sqrt(2)$