How do you solve $m- ( 2m + 1) = 8- ( 3m + 3)$ ?

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Answer 1 · 2017-07-27T21:31:36

$m - (2m + 1) = 8 - (3m + 3)$

$m - 2m - 1 = 8 - 3m - 3$

$-m - 1 = -3m + 5$

$2m = 6$

$m = 3$

How do you solve m- ( 2m + 1) = 8- ( 3m + 3)m- ( 2m + 1) = 8- ( 3m + 3)?